[snip]
Ok, I added the resource identifier, and got an error. I think what is
happening now is the resource identifier $db is outside the function
one(), so it cannot be referenced from the mysql_list_fields() fuction
which is inside. Does that make sense? Is the resource indentifier a
GLOBAL thing, because I sure didn't make it one :) The error I got was,
"supplied argument is not a valid Mysql-Link resource".
[/snip]
Add GLOBAL to the function ....
function one() {
global $db;
mysql_select_db("db");
$fields = mysql_list_fields("db", "table", $db);
}
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