Hello Jason,
Thanks for your snot. The code you wrote below,
> echo fopen("http://www.google.com";, 'r');
> echo fopen("http://news.google.com";, 'r');
I've implmented at this url.
http://www.globalscoop.com/gs/feeds/testUrl.php
You can see the error I'm getting. Would you take a look?
John
"Jason Wong" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> On Friday 07 November 2003 04:12, John Hagstrand wrote:
>
> > I'm trying to read a URL.
> >
> > this works: fopen( "http://www.google.com";)
> >
> > this does not work: fopen( "http://news.google.com";)
>
> As it stands, neither of the above will work. fopen() requires at least 2
> parameters. When you post code, please post the *exact* code that you use.
>
> > If the URL does not start with "www", then fopen writes and error
message
> > that says "success" and returns false. What's up with that?
>
> Did you jump to that conclusion based solely on the two example URLs
above?
>
> For the record:
>
> echo fopen("http://www.google.com";, 'r');
> echo fopen("http://news.google.com";, 'r');
>
> works fine for me.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
> ------------------------------------------
> Search the list archives before you post
> http://marc.theaimsgroup.com/?l=php-general
> ------------------------------------------
> /*
> Humans are communications junkies. We just can't get enough.
> -- Alan Kay
> */
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
