http://it.php.net/manual/it/function.is-integer.php
Cesar Cordovez ha scritto:
This is getting weird by the minute. I changed the script:
if ($number != $value) { echo "Bad"; } else { echo "Good"; // echoes Good!!!!!! }
to: ($number != $value) ($number !== $value) ($number === $value)
and I get the Good stuff...
At this point, I think I have to change the procedure. This is not good. Any sugestions on how to now if the user types an integer number in a field?
Cesar
Curt Zirzow wrote:
* Thus wrote Cesar Cordovez ([EMAIL PROTECTED]):
Curt:
My fault! You are right, but thats not what I want. $value comes from a form filled by a user. I want $value to be an integer. Not a float. So if the user types "12.3" the system has to send an error msg.
Yeah, after reading merek's response I realized I missed what exactly your problem is.
Therefore the procedure.
By-the-way, Im using PHP 4.3.3 (on windows XP profesional. Don't say a thing!!! I rather work on my mac!) =)
Thats odd, I come up with a 'Bad' echo also. The only thing I can think of is there is some sort of implicit casting happening to the $value within the comparison. But it does seem very strange that XP would cast but *nix doesn't
In that case test the condition reversed: if ($value != $number)
I'm at a loss as to why it doesn't work on your system.
Curt
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