hi, all,
I have this code at http://weiwang.freeshell.org/formprac.php and the execution kept
stuck at
the condition part of:
if(!isset($first)) {
show_form();
}
Even if I input some text into both field and click submit, the execution wouldn't go
to any other
conditional branch and be stuck at this one.
Any advice would be greatly appreciated.
Wei Wang
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>
<body>
<h2>Simple Form Example</h2>
<? function show_form($first="",$last="") { ?>
<form action="formprac.php" method="POST">
First Name:
<input type=text name=first value="<?echo $first?>">
<br>
Last Name:
<input type=text name=last value="<?echo $last?>">
<br>
<input type=submit>
</form>
<? }
if(!isset($first)) {
show_form();
}
else {
if(empty($first) or empty($last)) {
echo "You did not fill in all the
fields, try again<p>";
show_form($first,$last);
}
else {
echo "Thank you, $first $last";
}
}
?>
</body>
</html>
