this question was answered be me only two days ago. it would be nice to see people 
checking before they post.

<?php

 $db = mysql_connect('localhost', 'root', '*****');
 mysql_select_db('indywebdesign', $db);

 $query = 'SELECT * FROM invoices WHERE customerid = $id ORDER BY invoiceid DESC';
 $invoices_result = mysql_query($query);
 
 while($result = mysql_fetch_array($invoices_result))
  $invoices[] = $result;

?>


-- 

 Chris Lee
 [EMAIL PROTECTED]


""WreckRman2"" <[EMAIL PROTECTED]> wrote in message 
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I am having problems figuring out how to loop to show more then one
record... Any help would be great... All I can get is the first record...

Thanks...

Code:

<?php

$db = mysql_connect("localhost", "root", "*****");
mysql_select_db("indywebdesign",$db);

$invoices_result = mysql_query("select * from invoices WHERE customerid=$id
ORDER BY invoiceid DESC");
$invoices = mysql_fetch_array($invoices_result);

?>

<TR>
    <TD BGCOLOR="#EAEAEA"><FONT FACE="Tahoma" SIZE="2"><?php echo
$invoices["date"] ?></FONT></TD>
    <TD BGCOLOR="#EAEAEA"><FONT FACE="Tahoma" SIZE="2"><?php echo
$invoices["amount"] ?></FONT></TD>
    <TD BGCOLOR="#EAEAEA" COLSPAN="2"><FONT FACE="Tahoma" SIZE="2"><?php
echo $invoices["description"] ?></FONT></TD>
  </TR>


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