Re: [PHP] imagejpeg function output

[Marek Kilimajer]

You need to send the right header, in this case
header('Content-type: image/jpg');
Mike At Spy wrote:
Just to make sure no one is lead astray - I still have an issue getting jpeg
enabled on a server with gd and php.  I am asking this question 'cause I am
doing some work on a different server where jpeg is enabled.
Anyway, I have this sort of setup:

$src_img = imagecreatefromjpeg($rand_image);
         $dst_img = imagecreate($destWidth,$destHeight);
         imagecopyresized($dst_img, $src_img, 0, 0, 0, 0, $destWidth,$destHeight,
$srcWidth, $srcHeight);
         imageJPEG($dst_img, $dest_file, 100);
         imagedestroy($src_img);
	print $dest_file;

Now, from this I get a bunch of binary code like:

…•ª¸âq¼Ö”a µ*'ì ªNp䊤¡ r«V
ΦܿGà¾Çq¿å¼=‚©4±3u18º‹÷xj4ê%R£¥N¥J•j6ý•8FMN½Z~Öt©}bµdøŸûvjZˆ`ð÷Á¿?Þ.ø
‘eg3%ïÄ??CágÃKYûNÕ
Which I sort of expected.

BUT; how do I show the picture ($dest_file) in the browser from here?

Thanks,

-Mike

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