John Taylor-Johnston wrote:

My question got buried on the bottom of the thread. Sorry for the repeat. I'm getting this message:

Warning: Supplied argument is not a valid MySQL result resource in /.../testals.php on line 189

Read with me. Supplied argument ($news) is not a valid MySQL result resource.


189> if (mysql_num_rows($news) == 1)

Ideas?

$server = "localhost";
$user = "****";
$pass = "****";
$db = "redwards";
$table = "testals";

$myconnection = mysql_connect($server,$user,$pass);
mysql_select_db($db,$myconnection);

$news = mysql_query("select StudentId from $table where
StudentID = $StudentID");

$news is not valid, therefore your query failed. Use mysql_error() to find out why.


--
---John Holmes...

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