I can't speek about the first problem, but about the second one.
You are not setting the variable $blah as a global variable.
Try this instead
$GLOBALS['blah'] = 'bob';
and that should work.
You need to look into scope when refering to variables and functions.
Jim Lucas
----- Original Message -----
From: "Chris Boget" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Friday, August 01, 2003 12:03 PM
Subject: [PHP] Globals
> I'm curious if someone could explain to me why this is occuring:
>
> function blah() {
> //global $GLOBALS;
> echo 'Globals: <pre>'; print_r( $GLOBALS ); echo '</pre>';
>
> }
>
> As it is shown above, with the 'global $GLOBALS' line commented
> out, the print_r() works and shows all the currently defined variables
> and their corresponding values. However, if I declare $GLOBALS
> as global, nothing gets printed out.
>
> Why?
>
> Wouldn't the 'global $GLOBALS' line be more or less redundant in
> most cases? Because $GLOBALS is a superglobal (though, it isn't
> really)? Why would it affect whether or not $GLOBALS actually has
> the expected data inside the function?
>
> While I'm on this subject, why isn't $GLOBALS always a superglobal?
> For example, this doesn't work:
>
> function innerFunc() {
>
> echo $GLOBALS['blah'];
>
> }
>
> function outerFunc() {
>
> innerFunc();
>
> }
>
> $blah = 'bob';
> outerFunc();
>
> Nothing gets echoed from innerFunc(). Why? If anyone can offer
> any insight as to what is going on, I'd be ever so appreciative.
>
> Chris
>
>
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