I used your snip you just posted and changed the $Days = round(Days) to $Days = round($Days) and got 228.
-----Original Message----- From: Scott Fletcher [mailto:[EMAIL PROTECTED] Sent: Friday, August 01, 2003 9:18 AM To: [EMAIL PROTECTED] Subject: [PHP] Simple Math Calculation Problem.... Hi! I'm a little stuck with this simple math problem. I'm trying to get a number of days in integer, not float. --snip-- $input_date = "12/16/2002"; $UserInput = explode("/", $input_date); $UserInputMonth = $UserInput[0]; $UserInputDay = $UserInput[1]; $UserInputYear = $UserInput[2]; $clockDate = mktime(0,0,0,date("m"),date("d"),date("Y")); $inputDate = mktime(0,0,0,$UserInputMonth,$UserInputDay,$UserInputYear); $Days = (($clockDate - $inputDate) / (24 * 3600)); //$Days = round(Days); --snip-- But then I get the idea of doing the round function but it only return a '0' value. Anyone know? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
