Re: [PHP] uploading a file from a form

[Marek Kilimajer]

Everything is in the manual:
http://www.php.net/features.file-upload
Amanda McComb wrote:

I'm not sure what that means...how do I use it, and where?

On Fri, 25 Jul 2003, Marek Kilimajer wrote:


Don't you need to use $HTTP_POST_FILES array because you have 
register_globals off?

Amanda McComb wrote:


I am having a problem with uploading a file from a form.  I changed the
permission on the directory, but I am still getting an error.  Here is my
error:
Copy failed./home/vencel/www/images/apt/company_logo/14Update Failed!

It looks like it's not finding the file type.  Here is my code:

<? include("../includes/database.php"); ?>
<?
$long_path = "/home/vencel/www/images/apt/";
$short_path = "../images/apt/";
if (($REQUEST_METHOD=='POST')) {
  for(reset($HTTP_POST_VARS);
                     $key=key($HTTP_POST_VARS);
                     next($HTTP_POST_VARS)) {
        $this = addslashes($HTTP_POST_VARS[$key]);
        $this = strtr($this, ">", " ");
        $this = strtr($this, "<", " ");
        $this = strtr($this, "|", " ");
        $$key = $this;
  }
//Check for form fields, insert them.

//Pull out the id auto-incremented from previous insert.
 

//Check to see if a full-sized photo was uploaded
if ($photo == "none") { 
   echo "No photo.";
   } else {
     $end = strrchr($photo_name, ".");
echo $end;
     $new_photo_name = $company_id[0] . $end;
   
     if ([EMAIL PROTECTED]($photo, $long_path . "company_logo/" . $photo_name)) {
         echo "Copy failed.";
         echo $long_path . "company_logo/" . $photo_name;
echo $new_photo_name;
   
     } else {
       $long_photo_path = $long_path . "company_logo/" . $new_photo_name;
       $photo_path = $short_path . "company_logo/" . $new_photo_name;
   
       if ([EMAIL PROTECTED]($long_path . "logo/" . $photo_name,
          $long_photo_path)){
          echo "Full sized photo not renamed.";
       }
     }
   }
   $add_image_query .= "UPDATE apt_company_t set
company_logo_path='$photo_path', ";
   $add_image_query .= "WHERE company_cd = $company_id[0]";
     
   mysql_query($add_image_query) or die("Update Failed!");
     
   
   } 
} ?>
<FORM METHOD="post" ACTION=<? echo $PHP_SELF ?>>
<table>
<TR>
<td colspan = 2><B>Use the <i>Browse</i> button to locate your file on
your computer or local network.</B></td></tr>
                    
<tr>
<td>Company Logo File:      </td><td><input type="file" name="photo"
size="30"></td></tr>

<tr>
<td colspan=2 align=center><INPUT TYPE="submit" VALUE="Add"></td>
</tr>
</table>
</FORM>
Any ideas?






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