Take out the plus sign... type != 'Meal Plans' And using single quotes in your query might make things easier (no escaping...)
$dbqueryshipping1 = "select * from tempuserpurchase where usersessionid='$User_Shopping_Id' and day='1' and type!='Meal Plans'"; You don't need quotes around '1' since it's an integer, but MySQL is forgiving. ---John Holmes... ----- Original Message ----- From: "Phillip Blancher" <[EMAIL PROTECTED]> To: "PHP List" <[EMAIL PROTECTED]> Sent: Wednesday, July 23, 2003 5:08 PM Subject: [PHP] Problem with MySQL Query Problem with mySQL Query This is the query I have: $dbqueryshipping1 = "select * from tempuserpurchase where (usersessionid=\"$User_Shopping_Id\") and day=\"1\" and type!=\"Meal+Plans\" "; What I want to do is to select everything from tempuserpurchase that matchs the user session and the day, so long as type is not "Meal Plans" However it is not excluding "Meal Plans" Any Suggestions. Thanks in advance, Phil __________________ --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.501 / Virus Database: 299 - Release Date: 7/14/2003 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
