mysql_insert_id(); 

How would I call that in my query? Because I tried that and I get
resource ID=2 

Also putting it into a string and writing it to a file, sounds good to
me, that's what I was thinking but how do you do it? Can it just be
written as:
$string ="all my code including ";''=}{[] etc";
And then calling the string with fwrite? Or am I going to run into
serious problems?

Steve Jackson
Web Development and Marketing Manager
Viola Systems Ltd.
http://www.violasystems.com
[EMAIL PROTECTED]
Mobile +358 50 343 5159





> -----Original Message-----
> From: Andrew McCombe [mailto:[EMAIL PROTECTED] 
> Sent: 7. heinäkuuta 2003 16:05
> To: [EMAIL PROTECTED]; Steve Jackson
> Subject: Re: [PHP] How to insert a variable into a PHP template.
> 
> 
> 
> ----- Original Message ----- 
> From: "Steve Jackson" <[EMAIL PROTECTED]>
> To: "PHP General" <[EMAIL PROTECTED]>
> Sent: Monday, July 07, 2003 1:34 PM
> Subject: [PHP] How to insert a variable into a PHP template.
> 
> 
> > Hi,
> >
> > I want to write a PHP template with a variable number of the last 
> > recordset in a MySQL DB being the number referenced in the 
> file. This 
> > is so my file can be saved as a PHP page looking at the 
> right content 
> > in a database for a content management system. I am stuck 
> on the way 
> > to do it. The code below is the part I want to change:
> >
> > So I need to do two things:
> > 1) Select the last record in a database table.
> 
> 
> mysql_insert_id();
> 
> 
> 
> > 2) get PHP to write all the code below on the fly.
> >
> > ////////////////////////
> >   db_connect();
> > // This is the query number which needs to be changed and written 
> > every time as the last record in the DB
> >   $query = "select * from crm_content where PageID='1'";
> >   $result = mysql_query($query) or die("Error: Query failure 
> > with<BR>$query<BR>".mysql_error());
> >   while ($array = mysql_fetch_array($result))
> >   {
> >   $PageTitle = "{$array["Title"]}";
> >   $BodyText = "{$array["BodyText"]}";
> >   $Picture1 = "{$array["PictureOne"]}";
> >   $Picture2 = "{$array["PictureTwo"]}";
> >   $CatID = "{$array["CatID"]}";
> >   }
> > // then write the function to call the page here 
> > //////////////////////
> >
> > Any ideas thoughts or help much appreciated.
> >
> 
> Can't help with this bit.  Apart from putting it into a 
> string and then writing it to a file.
> 
> Regards
> Andrew
> 
> 


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