And thats why Chris is the man. Your're right it doesnt look pretty but it
works. If I come up with another solution I will email it out.
Thanks again,
Daniel
----- Original Message -----
From: "Chris Sherwood" <[EMAIL PROTECTED]>
To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Wednesday, June 25, 2003 3:11 PM
Subject: Re: [PHP] Passing Array to object
> function DisplayLinks($links,$names)
> {
> $namecount = sizeof($names);
> for($a=0;$a<$namecount;$a++)
> {
> $name = $names[$a];
> $url = $links[$a];
> echo ":::<a href= '$url''>$name</a>:::\n";
>
> } //End for
> } // End DisplayLinks function
>
> try this and assigning the names you want to be displayed to the names
array
> and links to the links array...
>
> I know this isnt pretty but it should work
> ----- Original Message -----
> From: "Daniel J. Rychlik" <[EMAIL PROTECTED]>
> To: "Chris Sherwood" <[EMAIL PROTECTED]>;
> <[EMAIL PROTECTED]>
> Sent: Wednesday, June 25, 2003 12:59 PM
> Subject: Re: [PHP] Passing Array to object
>
>
> > I remember seeing somewhere that you could only pass a single
deminsional
> > Array to a class. But I cant even get this one deminsional to work. If
I
> > place the links inside the main class and call it an attribute it works
> > fine.
> >
> > var $newlinks = array (...)'
> >
> > When I var_dump($myarray) I recieve the output as expected. For some
> > reason its still giving me the warning. hmmm...... Ive tried
everything
> > that was suggested. I think I need to go back and take another look at
OO
> > programming in php.
> >
> >
> > ----- Original Message -----
> > From: "Chris Sherwood" <[EMAIL PROTECTED]>
> > To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>;
> > <[EMAIL PROTECTED]>
> > Sent: Wednesday, June 25, 2003 1:46 PM
> > Subject: Re: [PHP] Passing Array to object
> >
> >
> > > hmmm okay
> > > cause list works by assigning elements in order from an array
> > > each iterates thru each element in a list so you want to pass both
> > elements
> > > at the same time so you need to pass an array to get the effect your
> > looking
> > > for
> > >
> > > ie $name being from the first array element, and $url being from the
> > second
> > > array element...
> > >
> > > so I am thinking you wish to assign urls and names to a single array
you
> > > will want to make it a multidimensional array
> > > ie array (array(name, link),array(name,link))
> > >
> > > hope this helps you daniel
> > >
> > > ----- Original Message -----
> > > From: "Daniel J. Rychlik" <[EMAIL PROTECTED]>
> > > To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>; "Chris Sherwood"
> > > <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
> > > Sent: Wednesday, June 25, 2003 11:17 AM
> > > Subject: Re: [PHP] Passing Array to object
> > >
> > >
> > > > Its erroring at my display links function. This function is inside
my
> > > main
> > > > class.
> > > >
> > > > function DisplayLinks($links) {
> > > >
> > > > while(list($name, $url) = each($links) {
> > > >
> > > > echo ":::<a href= '$url''>$name</a>:::\n";
> > > >
> > > > } //End while
> > > >
> > > > } // End DisplayLinks function
> > > >
> > > >
> > > > I dont see why it wont work... I even try assigning $links to the
> > array.
> > > >
> > > >
> > > > ----- Original Message -----
> > > > From: "Daniel J. Rychlik" <[EMAIL PROTECTED]>
> > > > To: "Chris Sherwood" <[EMAIL PROTECTED]>;
> > > > <[EMAIL PROTECTED]>
> > > > Sent: Wednesday, June 25, 2003 1:08 PM
> > > > Subject: Re: [PHP] Passing Array to object
> > > >
> > > >
> > > > > yea, I gave that a shot, Same message. Logically it makes sense,
but
> > php
> > > > > doesnt like it.
> > > > >
> > > > > by the way, thanks for your help Chris. You've helped me in the
> past.
> > > > > -Daniel
> > > > >
> > > > > ----- Original Message -----
> > > > > From: "Chris Sherwood" <[EMAIL PROTECTED]>
> > > > > To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>;
> > > > > <[EMAIL PROTECTED]>
> > > > > Sent: Wednesday, June 25, 2003 1:02 PM
> > > > > Subject: Re: [PHP] Passing Array to object
> > > > >
> > > > >
> > > > > > Have you tried to assign the array to a variable then pass the
> > > variable
> > > > to
> > > > > > the function ie
> > > > > >
> > > > > > $index = new main();
> > > > > > $yourvar = array('array values');
> > > > > >
> > > > > >
> > > > > > $index->SetLink ($yourvar);
> > > > > >
> > > > > > ----- Original Message -----
> > > > > > From: "Daniel J. Rychlik" <[EMAIL PROTECTED]>
> > > > > > To: <[EMAIL PROTECTED]>
> > > > > > Sent: Wednesday, June 25, 2003 10:46 AM
> > > > > > Subject: [PHP] Passing Array to object
> > > > > >
> > > > > >
> > > > > > Hello,
> > > > > >
> > > > > > I am developing a site that uses classes to reuse code and
> objects.
> > > > > >
> > > > > > I have in my main class a
> > > > > >
> > > > > > function SetLinks($newlinks) {
> > > > > >
> > > > > > $this->links = $newlinks;
> > > > > >
> > > > > > }
> > > > > >
> > > > > > And another function that displays them in the same class main {
> > > > > >
> > > > > >
> > > > > > I have another file called index.php that basically just passes
> > > > attributes
> > > > > > to the main class and the main class displays them.
> > > > > >
> > > > > > Im having a bit of trouble passing an array to the object
> > > > > >
> > > > > > in the index.php
> > > > > >
> > > > > > I create new.
> > > > > >
> > > > > > $index = new main();
> > > > > > $index->SetLink = array ( 'Link1' => 'link1.php',
> > > > > > ..... );
> > > > > >
> > > > > > When I run I recieve "Variable passed to each() is not an array
or
> > > > object
> > > > > "
> > > > > >
> > > > > > so I tried this
> > > > > >
> > > > > > $index->SetLink($newlink = array('link1' => ...);
> > > > > >
> > > > > > same error message. I was wondering if someone could shed some
> > light
> > > on
> > > > > > what Im doing wrong.
> > > > > >
> > > > > > Thanks
> > > > > > Daniel
> > > > > >
> > > > >
> > > > >
> > > > > --
> > > > > PHP General Mailing List (http://www.php.net/)
> > > > > To unsubscribe, visit: http://www.php.net/unsub.php
> > > > >
> > > >
> > > >
> > > > --
> > > > PHP General Mailing List (http://www.php.net/)
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> > > >
> > > >
> > >
> >
> >
>
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