Took me a minute to figure out what you are trying to do, but I think I have it now.
Try this. $result = "SELECT ptype, count(*) FROM mylist_slave WHERE and user='".$my_user."' and cno='".$my_ccno."' GROUP BY ptype"; this will return you the number of rows that is the same number of packages they have setup. Jim Lucas ----- Original Message ----- From: "Ryan A" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Saturday, June 14, 2003 8:26 PM Subject: [PHP] multiple count (*) from php? (last one got sent in error, this is the correct one) > Hi, > I have 5 tables which keep th details for 5 packages for a company... > a company may add however many packages they wish. > > When a company logs in I want to be able to tell them: > > you have $numberOfPackages entered: > package1 $one > package2 $two > package3 $three > package4 $four > package5 $five > > instead of running 5 "$result = "SELECT count(*) FROM mylist_slave WHERE > ptype =$inn and user='".$my_user."' and cno='".$my_ccno."'"; > > is there any any way to select all 5 differient tables in one select > count(*) statement? > > Thanks, > -Ryan > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
