Ok Tod, this is what I understood so far: 1) image.php should generate for you a barcode;
2) you placed an echo statement inside image.php and nothing happens Marek have good ideea: try to see the html source code, the code that is interpreted by your browser. the executable file ./image.php probably don't run. try to see, from your shell (i think you use linux) if u can run a php script. e.g.: ./myscript.php ----- Original Message ----- From: "Todd Cary" <[EMAIL PROTECTED]> To: "Alex Ciurea" <[EMAIL PROTECTED]> Cc: "php mailing" <[EMAIL PROTECTED]> Sent: Tuesday, June 03, 2003 6:22 PM Subject: Re: [PHP] This line does not execute... > Alex - > > The code I placed in the messsage is a copy and paste of the code from > the sample.php script provided by the author of the barcode class and it > agrees with the demo he has on his site. > > The "error" is that nothing is happening which I interpret as the file, > image.php is not being accessed (I put an Echo statement inside it and > it does not execute). Here is the complete block of code: > > if ($obj) { > > if ($obj->DrawObject($xres)) { > echo "<table align='center'><tr><td><img > src='./image.php?code=" . $barcode . "&style=" . $style . "&type=" . > $type . "&width=" . $width . "&height=" . $height . "&xres=" . $xres . > "&font=" . $font . "'></td></tr></table>"; > > // My debug code - this line executes! > echo "<table align='center'><tr><td><font > color='#FF0000'>Success: Barcode = " . $barcode . > "</font></td></tr></table>"; > } else { > echo "<table align='center'><tr><td><font color='#FF0000'>" . > ($obj->GetError()) . "</font></td></tr></table>"; > > // My debug code > echo "<table align='center'><tr><td><font > color='#FF0000'>Problem; Barcode = " . $barcode . > "</font></td></tr></table>"; > } > } else { > // My debug code > echo "<table align='center'><tr><td><font color='#FF0000'>Obj is > false; Barcode = " . $barcode . "</font></td></tr></table>"; > } > > > Alex Ciurea wrote: > > >did u made copy&paste with your code? > > > >yes? then why don't you try to use the path='image.php?blahblahmoreblah' > >???? > > > >no? then please give us more details about the error you're getting... > > > >good luck, > >Alex > > > > > >----- Original Message ----- > >From: "Todd Cary" <[EMAIL PROTECTED]> > >To: <[EMAIL PROTECTED]> > >Sent: Tuesday, June 03, 2003 6:03 PM > >Subject: [PHP] This line does not execute... > > > > > > > > > >>I am trying to get the Sample Barcode to run on my server, however the > >>following line does not execute: > >> > >> echo "<table align='center'><tr><td><img src='./image.php?code=" . > >>$barcode . "&style=" . $style . "&type=" . $type . "&width=" . $width . > >>"&height=" . $height . "&xres=" . $xres . "&font=" . $font . > >>"'></td></tr></table>"; > >> > >>To see if it is executing, I have an "Echo" statement in the script. > >> > >>The image.php file is in the same directory as the other script files. > >> What am I missing here? > >> > >>Todd > >>-- > >> > >> > >> > > > >. > > > > > > > > -- > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php