First thanks for your help!.. I have the variable passing OK to this html page below. But the filename is not making it to the <img src> tag. I think the syntax is off?? I'm thinking maybe the img src tage needs to be broken up to allow the $image var to process?
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Test image</title>
</head>
<body bgcolor="#000000" text="#ffffff">
<?$image = $_GET['img']; echo "<img src='$image' border=0>";
?> </body> </html>
Just add some Javascript to the links around your thumbnails, like this:
<a href="javascript:window.open('show_photo.php?img=image.jpg');">
Then you need to create a script called show_photo.php that takes the "img" var passed by the Javascript above and loads that image onto the page.
$image = $_GET['img'];
echo "<img src='$image' border=0>";
Hope that helps.
Monty
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
