I'm kind of confused right now... when I call preg_replace_callback with a
regular expression with brackets, sometimes I get an array back with multiple
elements like
array(3) {
[0]=>
string(19) "http://www.aol.com
"
[1]=>
string(0) ""
[2]=>
string(19) "http://www.aol.com
"
}
and I have no idea why... Why does the middle one have nothing in it? the
regular expression was
$dumb_body = preg_replace_callback ( '/'
//Case spaceURLspace
. '([\s]http:\/\/[^\s]+[\s])'
. '|'
//Case URLspace
. '(^http:\/\/[^\s]+[\s])'
. '|'
//Case spaceURL
. '([\s]http:\/\/[^\s]+$)'
. '|'
//Case URL
. '(^http:\/\/[^\s]+$)'
. '/i'
, array( &$this, "storeUrlCallback" ),
$dumb_body );
I am very confused at the point of the array in this function period... can
anyone help?
Josh.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
