> <TR>
> <TD ALIGN="left" COLSPAN="3" HEIGHT=20>
> <B>1 - 50</B>
> <FORM NAME="Second" ACTION="https://website/file.php"; METHOD="post">
> <INPUT TYPE="hidden" NAME="lstnumrows" VALUE="50">
> </TD>
> <TD ALIGN="left" CELLPADDING="0" CELLSPACING="0" HEIGHT=20 COLSPAN="5">
> <INPUT TYPE="image" NAME="pic2" ID="pic2" BORDER="0" SRC="Blankleft.gif">
> <INPUT TYPE="image" NAME="pic3" ID="pic3" BORDER="0" SRC="Forwardu.gif"
> onClick=document.Second.submit(); onMouseOver="change_it('pic3')"
> onMouseOut="change_back('pic3')">
> </FORM>
> </TD>
> </TR>

You don'y say which cell has the problem but, apart from placing the closing
td right after the image try to move the closing form tag out from the
table. At least in IE, </FORM> _allways_ produces that extra space no matter
what you do unless you use style sheets to set the form's bottom-margin
yourself.



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