> This is the code around line 30..... > $local_file = $feed; > $fp = fopen($local_file, "r"); > > Anyone have any ideas? I have looked over the manual and the only thing I > could find similar to this is in the comments. Apache was restarted.
I get the same thing so I'm working through it. But here are some ideas that may work for you: What are the permissions of the file in question? And do you know the exact path of the file? Also, is the first line above (line 29?) needed? Why not just use $feed as the filename?
Forgot to mention this. Pulling via http. Works in the browser, but not in the script. The line above is needed, but it has nothing to do with fopen. Using url instead of $file produces same error.
Chris
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