function ArrayCompare($array1, $array2)
{ $answer = new Array()
foreach ($array1 as $element)
{ if (($key = array_search($element, $array2)) === false)
{ $answer[$key] = $array2[$key];
}
}
return $answer;
}
this will return an array that is a copy of the first array with only those
elements that are not in array2. If you only want the first one either just
use the first one( foreach(){ ... break;}) or put a break in the if.
Tim Ward
Senior Systems Engineer
Please refer to the following disclaimer in respect of this message:
http://www.stivesdirect.com/e-mail-disclaimer.html
> -----Original Message-----
> From: Jimmy Bäckström [mailto:[EMAIL PROTECTED]]
> Sent: 05 March 2001 06:38
> To: PHP General List
> Subject: Function to compare an array with another array
>
>
> Shu!
> I need some help here.
> I have a script where I want to compare two arrays with
> eachother, and return one value from that does not exists in
> both arrays. I have an array of pictures id number created
> from a database query. I use sessions to save id numbers of
> pictures into an array. I want the first array to be compared
> to the second and return the first key/value-pair that are
> not found in the session array...
> Is there a way I can do this?
>
> Thankful for any help!
> /Broder B
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
