OK, using this code:
<?
echo "<table border=\"0\">\n";
echo "<tr>\n";
$photocount = 0;
while($row = mysql_fetch_array($result)) {
$smallpic = $row['smallpic'];
echo "<td>$smallpic</td>\n";
if (($photocount % 3) == 2) {
echo "</tr>\n<tr>\n";
}
$photocount++;
}
echo "</tr>\n";
echo "</table>";
?>
And 8 photos in the table, I'm getting this output:
<table border="0">
<tr>
<td>sm982438092.gif</td>
<td>sm982437452.gif</td>
<td>sm982439016.gif</td>
</tr>
<tr>
<td>sm982529915.gif</td>
<td>sm983222652.gif</td>
<td>sm983222686.gif</td>
</tr>
<tr>
<td>sm983222868.gif</td>
<td>sm983222919.gif</td>
</tr>
</table>
Great, except it's missing an end cell, and after a few hours fiddling about
with code last night, I still didn't get any further in working out how I
was going to echo a table cell even if data's missing. So, any help would
be appreciated.
Apologies for what're probably "easy" questions. I slog away at work all
day, come back hoping to get something productive done on this, and the
ol'brain won't take it. Frustrating, to say the least.
James.
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