Hmmm... I'm pretty sure 1%3 is equal to 1.
I'm suspecting you might be incrementing $photocount too early -- that is,
before the if (($photocount % 3) == 2) statement. That would certainly
explain the weirdness you're seeing.
--Todd
> -----Original Message-----
> From: Johnson, Kirk [mailto:[EMAIL PROTECTED]]
> Sent: Monday, February 26, 2001 1:57 PM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP] Table looking odd as a result of while loop?
>
>
> Is it because 1 % 3 is 0 with a remainder of 2? Looks like
> the code is doing
> just what it is written to do. The "if" evaluates to true on
> the second
> picture.
>
> Kirk
>
> -----Original Message-----
> From: James, Yz [mailto:[EMAIL PROTECTED]]
> Sent: Monday, February 26, 2001 2:55 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Table looking odd as a result of while loop?
>
>
> Hi all, This is probably something dumb I'm missing, but I
> am using the
> following code:
>
> echo "<table border=\"0\">\n";
>
> echo "<tr>\n";
> $photocount = 0;
>
> while($row = mysql_fetch_array($result)) {
> $smallpic = $row['smallpic'];
>
> if (($photocount % 3) == 2) {
> echo "</tr>\n<tr>\n";
> }
>
> (There are currently 8 pics that have been uploaded). As you
> can see that
> the first row has returned just two columns. I'd like the
> photos to be
> displayed in rows of three, and if there are only 8 pictures
> (or any othe
> number that's not directly divisible by three) to be
> displayed on the last
> row. At the moment it's doing it "upside down." Any ideas?
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail:
> [EMAIL PROTECTED]
>
