empty() fails when $var == 0
--Joe
On Sun, Feb 25, 2001 at 10:50:15AM -0800, Chris Adams wrote:
> On 25 Feb 2001 00:01:30 -0800, Mark Maggelet <[EMAIL PROTECTED]> wrote:
> >On Sat, 24 Feb 2001 17:51:07 +0100, Christian Reiniger
> >([EMAIL PROTECTED]) wrote:
> >>On Saturday 24 February 2001 17:18, PHPBeginner.com wrote:
> >>> in my preceding email I've written:
> >>>
> >>> if($var!='')
> >>>
> >>> will fix your all your worries without an intervention of a
> >strings
> >>> function.
> >>
> >>Except that it will throw a warning in PHP4 if $var is not set.
> >>=> isset () should be used.
> >
> >man, this is like the thread that will not die. isset() will return
> >true for an empty string, which is not what he wants. the right thing
> >to do is use
> >
> >if((isset($var))&&($var!=""))
>
> Isn't this a bit more legible:
>
> if (!empty($var))
>
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