Hi people,
the syntax below is what I intend to use it to write out the customer detail on a new
file according the customer ID. I only make it rough and short and did not go too
detail on it, have limited experience oho here in some way.
<?php
(db connection bit).....
$queryRequest = "SELECT * FROM TouristRequests WHERE
TouristRequestID='$TouristRequestID'";
$resultRequest = mysql_query($queryRequest);
// to write out the new output file
$fileName = "$TouristRequestID";
$fileName .= ".php3";
$htmlFile = fopen("$fileName", "w");
$linkToApp = "https://www.manageasy.com/" .
"requestDetail.php3?filename=$fileName&TouristRequestID=$TouristRequestID";
if (!($htmlFile)) {
print("file could not be opened.");
exit;
}
// Write out Page.
fputs($htmlFile, "<? \n");
fputs($htmlFile, "if(!(\$PHP_AUTH_USER)): \n");
fputs($htmlFile, " echo '<meta http-equiv=\"refresh\"
content=\"0;url=https://www.manageasy.com/requestDetail.php3?TouristRequestID=$TouristRequestID&filename=$fileName\">';
\n");
fputs($htmlFile, " exit; \n");
fputs($htmlFile, "endif \n");
fputs($htmlFile, "?> \n");
fputs($htmlFile, "<HTML>\n");
fputs($htmlFile, "<HEAD>\n");
fputs($htmlFile, "<TITLE>Customer detail</TITLE>\n");
(and blabla.... until the end of the file).
fputs($htmlFile, "</BODY>\n");
fputs($htmlFile, "</HTML>\n");
**********************************
And there is nothing in the file requestDetail.php3 beside the sniplet for db
connection like this:
<?php
$connection = mysql_connect("$localhost", "username", "password");
mysql_select_db("dbname", $connection);
?>
*****************************
Is this correct way to do this?
cheers
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for yourself"
