> > foo ($hash = array('var1'=>'value', 'var2'=>'value'));
> >should work.
> You don't need the $hash in that function call unless you need to use
> it later on in your main program, so you can just say:
>
> foo (array('var1'=>'value', 'var2'=>'value'));
that won't work (Lux's complaint) when foo() is declared function foo
(&$hash)
cause PHP cannot extract the reference of an array unbound to any PHP
variable.
There is only one exception, which is for objects created with new.
-- teodor
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