Re: [PHP] Problem!

[Stephan Ahonen]

<<1.
$date = "20010101";

How could I output 01 01 2001 (or make it 3 variables, like day, month,
year)?>>

$year = substr($date,0,4);
$month = substr($date,4,2);
$day = substr($date,6,2);

...Assuming that the date is stored in yyyymmdd format.


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