still did not work. Keep returning the same error when I do this:
$HotelName = mysql_fetch_row($resultHotel,1) or die(mysql_error());
And once again I am very sure there is data in the table.
and the error keep saying that : 1 is not Mysql index.
I don't see why? can anyone tell?
cheers
Jack
[EMAIL PROTECTED]
"There is nothing more rewarding than reaching the goal you set for
yourself"
----- Original Message -----
From: Christopher Allen <[EMAIL PROTECTED]>
To: Jacky@lilst <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, January 25, 2001 12:39 AM
Subject: Re: [PHP] warning 1 is not mysql result index
>
>
> I want to get the result from first row (the one next from ID field) of
the
> table using
> $HotelName = mysql_result($resultHotel,0,1) or die(mysql_error());
>
> A suggestion:
> Why don't you use mysql_fetch_row or any other function that reaches
> beyond just getting 1 field?
> this would be easier perhaps for you visualize the data you are trying to
> get.
>
> http://www.php.net/manual/en/function.mysql-fetch-row.php
>
>
>
>
>
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