> function downloadfile($url, $imageDir)
> {
> if(!$file = fopen($url , "r"))
> {
> echo ("couldn't open $url\n");
> }
> else
> {
> #fpassthru($file);
> if($file2 = fopen("/www/sinead/images/Full/Sinead200.jpg", "w"))
> {
> $content=fread($file, filesize("$file"));
> fwrite($file2, $content, filesize("$file"));
Having quotes on the $file arguments to filesize() is not right...
Hey, doesn't filesize() take the *path* to a file, not a file pointer?
Yeah, it does: http://php.net/filesize
So, like, you're asking for the filesize of a file named '1' or whatever the
file pointer id number is.
Actually, I don't think you can get a filesize() of a URL anyway...
You're going to just have to get like a million bytes or whatever you think
convenient, and loop until you got it all.
> echo ("$file2 created");
> }
> }
> }
> ?>
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