Edit report at http://bugs.php.net/bug.php?id=52194&edit=1
ID: 52194
User updated by: bubi1 at mailinator dot com
Reported by: bubi1 at mailinator dot com
Summary: incorrect behaviour when printing non existend array
index
Status: Bogus
Type: Bug
Package: *General Issues
Operating System: all
PHP Version: 5.3.2
New Comment:
Yes, i know that a string is an array of chars. Maybe i'm wrong,but i
remember once only the syntax $string{0} was working, non $string[0]
also.
Anyway, why this works?
php -r '$arr = 'test';var_dump($arr['rasmus']);'
still prints "t".
There is no key called "rasmus" in the $arr string...
Previous Comments:
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[2010-06-26 19:12:01] [email protected]
A string is an array of characters. You have:
$arr[0] = "test";
Therefore array index 0 on that string is:
$arr[0][0] which very logically is "t"
------------------------------------------------------------------------
[2010-06-26 18:29:04] bubi1 at mailinator dot com
Description:
------------
The code below is self explaining.
Test script:
---------------
php -r '$arr =
array('test');var_dump($arr[0][0]);var_dump(isset($arr[0][0]));'
Expected result:
----------------
NULL
bool(false)
Actual result:
--------------
string(1) "t"
bool(true)
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Edit this bug report at http://bugs.php.net/bug.php?id=52194&edit=1
