ID: 46611
Updated by: [EMAIL PROTECTED]
Reported By: fhardy at noparking dot net
Status: Assigned
Bug Type: MySQLi related
Operating System: FreeBSD 7.1-PRERELEASE
PHP Version: 5.2.6
-Assigned To: mysql
+Assigned To: andrey
New Comment:
Hi,
I have tried both 5.2.7RC4 and 5.3-dev (with libmysql and mysqlnd) and
can reproduce the problem. I have tracked the C/S traffic and there is
an error in the middle of the multi-statement, which cancels the whole
statement. I have added two var_dumps() to your example, like :
$sql = 'SET SQL_MODE=NO_AUTO_VALUE_ON_ZERO; DROP TABLE IF EXISTS
`bank_transactions`; CREATE TABLE `bank_transactions` ( `id` int(10)
unsigned NOT NULL AUTO_INCREMENT, `client_id` int(10) unsigned NOT NULL,
PRIMARY KEY (`id`), KEY `client` (`client_id`)) ENGINE=InnoDB DEFAULT
CHARSET=utf8 ROW_FORMAT=DYNAMIC; DROP TABLE IF EXISTS `clients`; CREATE
TABLE `clients` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, PRIMARY
KEY (`id`)) ENGINE=InnoDB DEFAULT CHARSET=utf8 ROW_FORMAT=DYNAMIC;
ALTER TABLE `bank_transactions` ADD CONSTRAINT
`bank_transactions_ibfk_1` FOREIGN KEY (`client_id`) REFERENCES
`clients` (`id`) ON UPDATE CASCADE';
$mysqli = new mysqli('127.0.0.1', 'root', 'root', 'db');
if ($mysqli->connect_error) {
printf('Connect failed: %s\n', mysqli_connect_error());
} else {
if (!$mysqli->multi_query($sql)) {
printf('Unable to execute sql');
} else {
do {
if ($result = $mysqli->store_result()) {
var_dump($result);
$result->free();
} else {
var_dump(mysqli_error($mysqli));
}
} while ($mysqli->next_result());
var_dump(mysqli_error($mysqli));
}
$mysqli->close();
}
and the output is :
[EMAIL PROTECTED]:~/dev/tmp/php5.2-200811191530$ ./php
../../vanilla/php5_3/a.php
string(0) ""
string(0) ""
string(54) "Can't create table 'db.bank_transactions' (errno: 150)"
[EMAIL PROTECTED]:~/dev/tmp/php5.2-200811191530$ ./php -v
PHP 5.2.7RC4-dev (cli) (built: Nov 19 2008 18:49:58)
Copyright (c) 1997-2008 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies
[EMAIL PROTECTED]:~/dev/tmp/php5.2-200811191530$
/work/mysql-server/mysql-5.1-binprot/extra/perror 150
MySQL error code 150: Foreign key constraint is incorrectly formed
----------
So I don't know why from the CLI the problem doesn't happen, it needs
further analyse to see why the environment is different. Also probably
needs a test case in C using libmysql, which will probably exhibit the
same problems.
Previous Comments:
------------------------------------------------------------------------
[2008-11-19 11:23:39] fhardy at noparking dot net
Table and constraint creation are ok with cli mysql client.
Table and constraint creation are ok with phpmyadmin with mysql php's
extension (i known that mysql php's extension has not multi_query()
equivalent method).
Removing "alter table... add constraint" from sql in php script resolve
the problem.
Execute several queries on mysql 5.1 RC server with
mysqli::multi_queries() without any "alter table... add constraint" is
ok.
In conclusion, All work fine between this mysql 5.1 RC version and
php's mysqli extension, except this.
So, I think that it must be interesting to check mysqli php's extension
compatibility with mysql 5.1, even if mysql version is a RC.
------------------------------------------------------------------------
[2008-11-19 10:57:52] [EMAIL PROTECTED]
How is this _PHP_ bug? Since all that changed is mysql version (to a
_release candidate_!) I find it funny you report this here..
------------------------------------------------------------------------
[2008-11-19 10:23:59] fhardy at noparking dot net
Description:
------------
Using mysqli::multi_query() in order to create database table in innodb
format with foreign key failed with mysql 5.1 RC.
All is fine with mysql 5.0.67
Reproduce code:
---------------
<?php
$sql = 'SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
DROP TABLE IF EXISTS `bank_transactions`;
CREATE TABLE `bank_transactions` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`client_id` int(10) unsigned NOT NULL,
PRIMARY KEY (`id`),
KEY `client` (`client_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 ROW_FORMAT=DYNAMIC;
DROP TABLE IF EXISTS `clients`;
CREATE TABLE `clients` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 ROW_FORMAT=DYNAMIC;
ALTER TABLE `bank_transactions` ADD CONSTRAINT
`bank_transactions_ibfk_1` FOREIGN KEY (`client_id`) REFERENCES
`clients` (`id`) ON UPDATE CASCADE;';
$mysqli = new mysqli('myhost', 'myuser', 'mypassword', 'mydatabase');
if ($mysqli->connect_error) {
printf('Connect failed: %s\n', mysqli_connect_error());
} else {
if (!$mysqli->multi_query($sql)) {
printf('Unable to execute sql');
} else {
do {
if ($result = $mysqli->store_result()) {
$result->free();
}
} while ($mysqli->next_result());
}
$mysqli->close();
}
?>
Expected result:
----------------
Database "mydatabase" must contain two tables, clients and
bank_transactions, and one constraint between this tables.
Actual result:
--------------
I have an empty database and no error message from mysqli object.
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=46611&edit=1
