I'm coming back to this because I've been bitten by these floating points things again.
If in Pharo [1] you do: a := 6.7 + (32.8 - 35) It will produce: 4.499999999999997 Which, when rounded, will produce 4. In other places [2] I do the same simple addition and subtraction it produces 4.5, that when rounded will produce 5. I know now that Pharo doesn't lie to me while other systems do, and all that Richard pointed to before. The issue here is that I'm following some calculation formula that was defined in some of the "other" systems, and so when I follow such a formula I get these edgy cases where my system produces a different output. In this case the formula is for golf handicap calculations, and it caused my system to give 4 instead of 5 to a player, resulting in giving the first place to a player other than the one deserved. It was no big deal (it's not The Masters), but these cases appear from time to time. Is there any way to "configure" the floating point calculation to behave as the "other systems"? What is the best way to anticipate these situations, am I the only one being bitten by these issues? Thanks in advance for any hints about these problems. Best regards, [1] Dolphin Smalltalk, JS, Python, Ruby, Dart produces the same output as Pharo. [2] VisualWorks, VAST, Excel, VB and all calculators I tried Esteban A. Maringolo On Tue, Sep 8, 2020 at 12:45 AM Esteban Maringolo <emaring...@gmail.com> wrote: > > On Tue, Sep 8, 2020 at 12:16 AM Richard O'Keefe <rao...@gmail.com> wrote: > > > > "7.1 roundTo: 0.1 should return 7.1" > > You're still not getting it. > > I was until Konrad explained it. > > > Binary floating point CANNOT represent either of those numbers. > > You seem to be assuming that Pharo is making some mistake. > > It isn't. All it is doing is refusing to lie to you. > <snip> > > The systems that print 7.1 are LYING to you, > > and Pharo is not. > > I'm not assuming a mistake from Pharo, I had a wrong expectation what > to get if I round to that precision. > I don't know whether other systems lie or simply fulfill user > expectations, if you send the #roundTo: to a float, I did expect to > get a number with the same precision. > That is my expectation as a user. As in the other thread I expected > two scaled decimals that are printed equal to also be compared as > equal (which they don't). > > Whether there is a good reason for those behaviors is beyond my > current comprehension, but it certainly doesn't follow the "principle > of least surprise". > > In any case, the method proposed by Tomohiro solved my issues. > > Regards, > > Esteban A. Maringolo
