That did it and it makes sense. Thanks so much!
> On Dec 17, 2014, at 11:36 PM, Guillaume Larcheveque
> <guillaume.larcheve...@gmail.com> wrote:
>
> So you just have to remove the #star in notA or replace it by #plus to makes
> it succeed only when it consume at least one character
>
> 2014-12-18 7:54 GMT+01:00 Guillaume Larcheveque
> <guillaume.larcheve...@gmail.com <mailto:guillaume.larcheve...@gmail.com>>:
> With x, x it will only go to 2 level deep.
>
> With the plus you allow to go as far as the x rule succeed and your x rule
> always succeed because notA always succeed due to the star without consuming
> anything so you fall into infinite loop.
>
> 2014-12-18 6:47 GMT+01:00 James Foster <smallt...@jgfoster.net
> <mailto:smallt...@jgfoster.net>>:
> There is something about plus that I don’t understand. In the following code
> if I parse for (x , x) then I get what I expect. If I parse for (x plus) then
> the image hangs. What am I doing wrong?
>
> James
>
> | a notA x y |
> a := $a asParser.
> notA := $a asParser negate star flatten.
> x := a / notA.
> y := x , x. “works fine”
> y := x plus. “never finishes”
> ^y end parse: 'ab’.
>
>
>
>
> --
> Guillaume Larcheveque
>
>
>
> --
> Guillaume Larcheveque
>
