no, don't do it
regular _id are taken as usual.
__id fields are references to another collection documents inside one document
(something that mongo does not have by itself).
And I like like that :)
Esteban
On Jul 8, 2013, at 2:38 PM, Esteban A. Maringolo <emaring...@gmail.com> wrote:
> But, as far as I know, Mongo will create an _id key with an Mongo OID
> for every document that doesn't have one.
> You can use _id without having to use an OID, you can use plain
> strings or integers.
>
> So I guess it is safe to use _id. I'll change it in my tests and then
> let you know.
>
> :)
> Esteban A. Maringolo
>
>
> 2013/7/8 Esteban Lorenzano <esteba...@gmail.com>:
>> Because _id is internally used by mongo and I didn't wanted to risk any
>> collision :)
>>
>> On Jul 8, 2013, at 2:26 PM, "Esteban A. Maringolo" <emaring...@gmail.com>
>> wrote:
>>
>>> Esteban,
>>>
>>> Why do you use __id: (double underscore) instead of the _id (single
>>> underscore) key?
>>>
>>> Regards,
>>> Esteban A. Maringolo
>>>
>>>
>>> 2013/7/8 Esteban Lorenzano <esteba...@gmail.com>:
>>>> Hi again,
>>>>
>>>> sadly, there is no direct support for referenced queries yet.
>>>>
>>>> however, you can workaround the problem by doing:
>>>>
>>>>
>>>> {
>>>> 'referenceField.__id' -> (VORepository current keyOf: referenceObject)
>>>> } asDictionary.
>>>>
>>>> or with MongoQueries:
>>>>
>>>> [ :each | (each at: 'referenceField.__id') = (VORepository current keyOf:
>>>> referenceObject) ]
>>>>
>>>> Some internal info:
>>>> in Voyage, all references are kept in mongo as sub-documents with this
>>>> structure:
>>>>
>>>> {
>>>> '__id': OID(1234567890).
>>>> '#collection': 'theNameOfTheCollection'.
>>>> }
>>>>
>>>> so, you always can construct queries knowing that :)
>>>>
>>>> Esteban
>>>>
>>>> On Jul 8, 2013, at 12:58 PM, Bernat Romagosa
>>>> <tibabenfortlapala...@gmail.com> wrote:
>>>>
>>>> Also, how does one query a referenced object?
>>>>
>>>> MyClass selectMany: { 'project.name' -> 'Test' } asDictionary. "<-- Works
>>>> only if project is an embedded object, but it doesn't if it's a reference."
>>>>
>>>>
>>>> 2013/7/8 Bernat Romagosa <tibabenfortlapala...@gmail.com>
>>>>>
>>>>> Sorry for being lazy, but how does one use logical operators in dictionary
>>>>> queries?
>>>>>
>>>>> I'm trying something like:
>>>>>
>>>>> (User selectMany: { 'profile.firstName' -> { '$regex' -> '^.*na.*'.
>>>>> '$options' -> 'i'} asDictionary } asDictionary).
>>>>>
>>>>> And I'd like to $or this with:
>>>>>
>>>>> 'profile.surname' -> { '$regex' -> '^.*ve.*'. '$options' -> 'i'}
>>>>> asDictionary.
>>>>>
>>>>>
>>>>> 2013/7/6 Stéphane Ducasse <stephane.duca...@inria.fr>
>>>>>>
>>>>>>
>>>>>> On Jul 6, 2013, at 11:16 AM, Esteban Lorenzano <esteba...@gmail.com>
>>>>>> wrote:
>>>>>>
>>>>>>> sure :)
>>>>>>>
>>>>>>> I will add a blog post on "voyage advanced queries" too :)
>>>>>>
>>>>>> too if you want but we could also focus on the chapter because we can be
>>>>>> multiple people to edit it
>>>>>> while your blog you are alone.
>>>>>>
>>>>>> Stef
>>>>>>
>>>>>>>
>>>>>>> Esteban
>>>>>>>
>>>>>>> On Jul 6, 2013, at 10:52 AM, Stéphane Ducasse
>>>>>>> <stephane.duca...@inria.fr> wrote:
>>>>>>>
>>>>>>>> esteban could you take some time to add this information to the Voyage
>>>>>>>> chapter?
>>>>>>>>
>>>>>>>> https://ci.inria.fr/pharo-contribution/job/PharoForTheEnterprise/
>>>>>>>>
>>>>>>>> add the information in any format and I can make it run.
>>>>>>>>
>>>>>>>>
>>>>>>>> https://github.com/SquareBracketAssociates/PharoForTheEnterprise-english
>>>>>>>>
>>>>>>>> Stef
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>> On Jul 4, 2013, at 7:49 PM, Esteban Lorenzano <esteba...@gmail.com>
>>>>>>>> wrote:
>>>>>>>>
>>>>>>>>> you have different constructions:
>>>>>>>>>
>>>>>>>>> { $gt: { "number_field": 42 } }
>>>>>>>>>
>>>>>>>>> and so on... always with dictionaries (bah, json structs).
>>>>>>>>>
>>>>>>>>> as a query language it kinda sucks... but well... is how it is :)
>>>>>>>>>
>>>>>>>>> On Jul 4, 2013, at 7:34 PM, Stéphane Ducasse
>>>>>>>>> <stephane.duca...@inria.fr> wrote:
>>>>>>>>>
>>>>>>>>>> Ok but how do I map conceptual a query to a dictionary
>>>>>>>>>>
>>>>>>>>>> Do I guess right that there is an exact match
>>>>>>>>>>
>>>>>>>>>> selectOne: { id -> 10} asDictionary
>>>>>>>>>>
>>>>>>>>>> will match id = 10
>>>>>>>>>>
>>>>>>>>>> Now we can only do exact mathc?
>>>>>>>>>>
>>>>>>>>>> name matches: 'stef*'
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On Jul 4, 2013, at 6:04 PM, Esteban A. Maringolo
>>>>>>>>>> <emaring...@gmail.com> wrote:
>>>>>>>>>>
>>>>>>>>>>> Stef,
>>>>>>>>>>>
>>>>>>>>>>> You're asking the other Esteban, but having used Voyage and Mongo I
>>>>>>>>>>> think I can answer this.
>>>>>>>>>>>
>>>>>>>>>>> Mongo receives a JSON object to do all the query filtering. For a
>>>>>>>>>>> simple lookup it is has a simple structre, as the query gets more
>>>>>>>>>>> complex it gets esoteric as well (with "special" MongoDB keys in
>>>>>>>>>>> the
>>>>>>>>>>> format of "$key").
>>>>>>>>>>>
>>>>>>>>>>> Because the simplest map we have to a JSON Object is the
>>>>>>>>>>> Dictionary, I
>>>>>>>>>>> guess that's why it ends up being converted to a Dictionary, which
>>>>>>>>>>> in
>>>>>>>>>>> turn gets converted to JSON and/or BSON.
>>>>>>>>>>>
>>>>>>>>>>> Regards,
>>>>>>>>>>>
>>>>>>>>>>> Esteban A. Maringolo
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> 2013/7/4 Stéphane Ducasse <stephane.duca...@inria.fr>:
>>>>>>>>>>>>
>>>>>>>>>>>> On Jul 4, 2013, at 2:58 PM, Esteban Lorenzano
>>>>>>>>>>>> <esteba...@gmail.com> wrote:
>>>>>>>>>>>>
>>>>>>>>>>>> Hi :)
>>>>>>>>>>>>
>>>>>>>>>>>> can you check if you have the "MongoQueries" package installed?
>>>>>>>>>>>>
>>>>>>>>>>>> cheers,
>>>>>>>>>>>> Esteban
>>>>>>>>>>>>
>>>>>>>>>>>> ps: please notice that in anycase you will not be able to execute
>>>>>>>>>>>>
>>>>>>>>>>>> [ :each | each name first = $X ]
>>>>>>>>>>>>
>>>>>>>>>>>> because the MongoQueries package just translates the block into a
>>>>>>>>>>>> mongo-query which is a dictionary (a JSON expression). But you
>>>>>>>>>>>> will found
>>>>>>>>>>>> some ways to help you, some special keywords like #in: and #where:
>>>>>>>>>>>> (you can
>>>>>>>>>>>> see how they work in the tests)
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> esteban
>>>>>>>>>>>> how a dictionary is used to work as a block for a query?
>>>>>>>>>>>> Can you explain because I would have thought that the first line
>>>>>>>>>>>> did not
>>>>>>>>>>>> work and the second would work.
>>>>>>>>>>>>
>>>>>>>>>>>> Stef
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> On Jul 4, 2013, at 2:17 PM, Bernat Romagosa
>>>>>>>>>>>> <tibabenfortlapala...@gmail.com>
>>>>>>>>>>>> wrote:
>>>>>>>>>>>>
>>>>>>>>>>>> Hi!
>>>>>>>>>>>>
>>>>>>>>>>>> I realize probably only Esteban will be able to answer, but I
>>>>>>>>>>>> prefer to
>>>>>>>>>>>> write to the list so the mail is logged and other people can
>>>>>>>>>>>> benefit from
>>>>>>>>>>>> it.
>>>>>>>>>>>>
>>>>>>>>>>>> I'm trying to use blocks as arguments for #selectOne: and
>>>>>>>>>>>> #selectMany:, but
>>>>>>>>>>>> it doesn't seem to work. Here's my code:
>>>>>>>>>>>>
>>>>>>>>>>>> MyClass selectOne: { #name -> 'Some name' } asDictionary.
>>>>>>>>>>>> MyClass selectOne: [ :each | each name = 'Some name' ].
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> The first one works, but the second one raises a
>>>>>>>>>>>> VOMongoConnectionError.
>>>>>>>>>>>>
>>>>>>>>>>>> Also:
>>>>>>>>>>>>
>>>>>>>>>>>> MyClass selectMany: { #name -> 'Some name' } asDictionary.
>>>>>>>>>>>> MyClass selectMany: [ :each | each name = 'Some name' ].
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> The first does work, the second one doesn't, which prevents me
>>>>>>>>>>>> from writing
>>>>>>>>>>>> more useful stuff like:
>>>>>>>>>>>>
>>>>>>>>>>>> MyClass selectMany: [ :each | each name first = $P ].
>>>>>>>>>>>>
>>>>>>>>>>>> Any idea why this could be failing? I've the latest stable version
>>>>>>>>>>>> loaded
>>>>>>>>>>>> via:
>>>>>>>>>>>>
>>>>>>>>>>>> Gofer it
>>>>>>>>>>>> url: 'http://smalltalkhub.com/mc/estebanlm/Voyage/main';
>>>>>>>>>>>> package: 'ConfigurationOfVoyageMongo';
>>>>>>>>>>>> load.
>>>>>>>>>>>> (Smalltalk at: #ConfigurationOfVoyageMongo) load.
>>>>>>>>>>>>
>>>>>>>>>>>> Thanks! :)
>>>>>>>>>>>>
>>>>>>>>>>>> Bernat.
>>>>>>>>>>>>
>>>>>>>>>>>> --
>>>>>>>>>>>> Bernat Romagosa.
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>
>>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Bernat Romagosa.
>>>>
>>>>
>>>>
>>>>
>>>> --
>>>> Bernat Romagosa.
>>>>
>>>>
>>>
>>
>>
>
