Unless I overlooked something here, does this work ?
SELECT no, name, MAX(similarity(name, 'Tooneyvara')) AS sim
FROM vtown
WHERE similarity(name, 'Tooneyvara') > 0.4
GROUP BY no, name
ORDER BY sim DESC
--
Robins Tharakan
On 11/08/2011 02:50 AM, Tarlika Elisabeth Schmitz wrote:
Hello,
I would like to GROUP the result by one column and ORDER it by another:
SELECT
no, name, similarity(name, 'Tooneyvara') AS s
FROM vtown
WHERE similarity(name, 'Tooneyvara')> 0.4
ORDER BY s DESC
Result:
1787 "Toomyvara" 0.5
1787 "Toomevara" 0.4
1188 "Toonybara" 0.4
Desired result:
1787 "Toomyvara" 0.5
1188 "Toonybara" 0.4
Gets rid of the duplicate "no" keeping the spelling with the greater
similarity and presents the remaining result ordered by similarity.
My solution:
SELECT * FROM
(
SELECT DISTINCT ON (no)
no, name,
similarity(name, 'Tooneyvara') AS sim
FROM vtown
WHERE similarity(name, 'Tooneyvara')> 0.4
ORDER BY no, sim DESC
) AS x
ORDER BY sim
Is that the best way to achieve this result?
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