"Pavan Deolasee" <[EMAIL PROTECTED]> writes:
> I think you are assuming that the next write of the same block won't
> use another OS cache block. I doubt if thats the way writes are handled
> by the kernel. Each write would typically end up being queued up in the
> kernel
> where each write will have its own copy of the block to the written. Isn't
> it ?
A kernel that worked like that would have a problem doing read(), ie,
it'd have to search to find the latest version of the block. So I'd
expect that most systems would prefer to keep only one in-memory copy
of any given block and overwrite it at write() time. No sane kernel
designer will optimize write() at the expense of read() performance,
especially when you consider that a design as above really pessimizes
write() too --- it does more I/O than is necessary when the same block
is modified repeatedly in a short time.
regards, tom lane
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