Hello: I find that the real timestamp format(got from the file which is produced by copying binary to ) is different from what i find in timestamp_send func.
i do think that the binary format of a timestamp "2006-04-18 11:20:20" should be "44 2B B0 6A 00 00 00 00" standing for "secs:1143713898, usecs:0" but in fact it is:"41A7 7DBA D400 0000 " timestamp is defined as int64 or float8, when it is defined as int64, it looks like timeval, first 32 bits for seconds,second 32 bits for usec. and from the timestamp_send func, it just changes the first 32 bits to binary then combines the next 32 bits /* codes from timestamp_send */ Datum timestamp_send(PG_FUNCTION_ARGS) { Timestamp timestamp = PG_GETARG_TIMESTAMP(0); StringInfoData buf; pq_begintypsend(&buf); #ifdef HAVE_INT64_TIMESTAMP pq_sendint64(&buf, timestamp); #else pq_sendfloat8(&buf, timestamp); #endif PG_RETURN_BYTEA_P(pq_endtypsend(&buf)); } /* codes from pq_sendint64 */ void pq_sendint64(StringInfo buf, int64 i) { uint32 n32; /* High order half first, since we're doing MSB-first */ #ifdef INT64_IS_BUSTED /* don't try a right shift of 32 on a 32-bit word */ n32 = (i < 0) ? -1 : 0; #else n32 = (uint32) (i >> 32); #endif n32 = htonl(n32); appendBinaryStringInfo(buf, (char *) &n32, 4); /* Now the low order half */ n32 = (uint32) i; n32 = htonl(n32); appendBinaryStringInfo(buf, (char *) &n32, 4); } so i do think that the binary format of a timestamp "2006-04-18 11:20:20" should be "44 2B B0 6A 00 00 00 00" standing for "secs:1143713898, usecs:0" but in fact it is:" 41A7 7DBA D400 0000 " , i don't know why. maybe, i have looked into a wrong func, then which is the right one? ---------------------------(end of broadcast)--------------------------- TIP 4: Have you searched our list archives? http://archives.postgresql.org