-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 hello
once again :) the code is this: text *src; void *tmp; src = (text*)tmp; and the error message: error: parse error before `)' token (at (text*_)_) originally i've tried to use the macro PG_GETARG_TEXT_P(0), but when i've got this message, i've asked the preprocessor for the preprocess code, to get this makro resolved. after i've resolved the macro: ((text *)pg_detoast_datum((struct varlena *)((Pointer)(fcinfo->arg[0])))) i've got this. what's the problem with the (text*) casting? Bye, Gergely Czuczy mailto: [EMAIL PROTECTED] PGP pubkey: http://phoemix.harmless.hu/phoemix.pgp iRCNet: #demoscene ICQ: 8067175 The point is, that geeks are not necessarily the outcasts society often believes they are. The fact is that society isn't cool enough to be included in our activities. -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.0.6 (GNU/Linux) Comment: For info see http://www.gnupg.org iD8DBQE/VKxHbBsEN0U7BV0RAqSsAJ997nmsbPeeC9O1MlJF44ZeUIGW0wCgzTTx moUw1UBTFs+nIM+q7josTlU= =35gD -----END PGP SIGNATURE----- ---------------------------(end of broadcast)--------------------------- TIP 5: Have you checked our extensive FAQ? http://www.postgresql.org/docs/faqs/FAQ.html
