Paul Matthews <p...@netspace.net.au> wrote: > Feedback appreciated. + /* As x is the larger value, this must be the correct answer. Also + * avoids division by zero. */ + if( x == 0.0 ) + return 0.0; + + /* Trivial case. */ + if( y == 0.0 ) + return x; The first test seems unnecessary if you have the second. x >= 0, so x can't be zero unless y is, too. Returning x on y == 0.0 will return 0.0 whenever x == 0.0. -Kevin
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