Hi Amit, On Wed, Sep 4, 2019 at 3:30 PM Richard Guo <ri...@pivotal.io> wrote:
> Hi Amit, > > On Wed, Sep 4, 2019 at 10:01 AM Amit Langote <amitlangot...@gmail.com> > wrote: > >> Fujita-san, >> >> To avoid losing track of this, I've added this to November CF. >> >> https://commitfest.postgresql.org/25/2278/ >> >> I know there is one more patch beside the partitionwise join fix, but >> I've set the title to suggest that this is related mainly to >> partitionwise joins. >> > > Thank you for working on this. Currently partitionwise join does not > take COALESCE expr into consideration when matching to partition keys. > This is a problem. > > BTW, a rebase is needed for the patch set. > I'm reviewing v2-0002 and I have concern about how COALESCE expr is processed in match_join_arg_to_partition_keys(). If there is a COALESCE expr with first arg being non-partition key expr and second arg being partition key, the patch would match it to the partition key, which may result in wrong results in some cases. For instance, consider the partition table below: create table p (k int, val int) partition by range(k); create table p_1 partition of p for values from (1) to (10); create table p_2 partition of p for values from (10) to (100); So with patch v2-0002, the following query will be planned with partitionwise join. # explain (costs off) select * from (p as t1 full join p as t2 on t1.k = t2.k) as t12(k1,val1,k2,val2) full join p as t3 on COALESCE(t12.val1, t12.k1) = t3.k; QUERY PLAN ---------------------------------------------------------- Append -> Hash Full Join Hash Cond: (COALESCE(t1.val, t1.k) = t3.k) -> Hash Full Join Hash Cond: (t1.k = t2.k) -> Seq Scan on p_1 t1 -> Hash -> Seq Scan on p_1 t2 -> Hash -> Seq Scan on p_1 t3 -> Hash Full Join Hash Cond: (COALESCE(t1_1.val, t1_1.k) = t3_1.k) -> Hash Full Join Hash Cond: (t1_1.k = t2_1.k) -> Seq Scan on p_2 t1_1 -> Hash -> Seq Scan on p_2 t2_1 -> Hash -> Seq Scan on p_2 t3_1 (19 rows) But as t1.val is not a partition key, actually we cannot use partitionwise join here. If we insert below data into the table, we will get wrong results for the query above. insert into p select 5,15; insert into p select 15,5; Thanks Richard
