Thank you Michael, your suggestion works a charm (though I didn't bother coalescing the two grp because I think the USING takes care of that anyway.
Paul On 7/8/05, Michael Fuhr <[EMAIL PROTECTED]> wrote: > SELECT coalesce(g.grp, b.grp) AS grp, > coalesce(g.count, 0) AS countgood, > coalesce(g.sum, 0) AS sumgood, > coalesce(b.count, 0) AS countbad, > coalesce(b.sum, 0) AS sumbad > FROM > (SELECT grp, count(good), sum(good) FROM lefty GROUP BY grp) AS g > FULL OUTER JOIN > (SELECT grp, count(bad), sum(bad) FROM righty GROUP BY grp) AS b USING (grp); ---------------------------(end of broadcast)--------------------------- TIP 2: Don't 'kill -9' the postmaster
