"Vladimir S. Petukhov" <[EMAIL PROTECTED]> writes:
> select * from nets;
> name | note | net
> ------+------+---------------
> | | 172.16.0.0/16
> (1 row)
> select * from nets where net >>= '172.16.4.0/8';
> name | note | net
> ------+------+-----
> (0 rows)
Are you confusing >>= with <<= perhaps? The >>= operator tests
ip_bits(a1) <= ip_bits(a2)
&& bitncmp(ip_addr(a1), ip_addr(a2), ip_bits(a1)) == 0
which looks reasonable enough to me. By that logic a /16 net
can never be a supernet of a /8 net.
regards, tom lane
---------------------------(end of broadcast)---------------------------
TIP 9: the planner will ignore your desire to choose an index scan if your
joining column's datatypes do not match
