-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi,
> .... where sqrt(pow((lat1 - lat2),2) + pow((long1 - long2),2)) >= 50 I assume that you dont want to deal with distances > 1000km?! > of the records that aren't in question anyways. How do you come to the > lat/long values for the max difference? Is there a general formula for > that? You can problably resort to simplified formulas like this: latitude: 1 degree ~~ 111km longitude: 1 degree ~~ 111km * cos( reference latitude ) > (I hated math all my life ;-) ) The whole thing is likely to get tough for you then ;-) Mit freundlichem Gruß / With kind regards Holger Klawitter - -- lists <at> klawitter <dot> de -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.2.2 (GNU/Linux) iD8DBQFBqtqg1Xdt0HKSwgYRAmgJAJ9+PCiWIbnA2HR6QiGBlLXp9OQT6wCgg+gF rL3xzK6UP9AUFsnWxpk4zoE= =GQ0I -----END PGP SIGNATURE----- ---------------------------(end of broadcast)--------------------------- TIP 2: you can get off all lists at once with the unregister command (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])