All, thanks for the many suggestions Alex
Manfred Koizar wrote:
On Thu, 20 Nov 2003 16:52:37 +0900, Alex <[EMAIL PROTECTED]> wrote:
Is there an easy way to write a select statement that returns me the
frist free number or any within the range of 200?
For example if 1-30, and 32-50 are occupied then i would like to fill in
the new entry with id 31.
Fortunately this is not the performance mailing list :-)
First free number: SELECT max(t1.id) + 1 FROM t AS t1 INNER JOIN t AS t2 ON (t1.id < 200 AND t1.id < t2.id AND t2.id <= 200) GROUP BY t2.id HAVING max(t1.id) + 1 < t2.id ORDER BY t2.id LIMIT 1;
Make sure that there is always a row with id=0 and a row with id=200.
Any free number: SELECT id - 1 FROM t WHERE 1 < id AND id <= 200 AND NOT EXISTS (SELECT * FROM t AS t2 WHERE t2.id = t.id - 1) LIMIT 1;
Always having a row with id=200 helps avoid unwanted corner cases.
One more: SELECT coalesce(max(id), 0) + 1 FROM t WHERE id <= 200 AND id = (SELECT count(*) FROM t AS t2 WHERE t2.id <= t.id);
This should work without any dummy rows. And it will not work, if id is not unique or there is any row with id < 1.
Servus Manfred
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