David G. Johnston wrote: >> It works for me on Linux with 9.6.3 psql: > > Except you haven't recreated the scenario I presented. > > You only are involving a single script and that script defines > "testfunction" itself > (which makes exporting pointless). In my example the script being executed > within the > psql script does not define testfunction itself. > > -> == execute in subshell > > main-script (def func) -> psql -> psql-call-bash (invoke func)
I am confused; my shell script does *not* contain a function definition. I copied and pasted a shell session: First, show the script that contains a function invocation. Then, define and export the function. Then, call psql Then, escape to a subshell. Then, call the script that successfully calls the function. Am I missing something? Yours, Laurenz Albe -- Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
