Alexander Reichstadt <i...@apfeltaste.net> writes:
> I think I solved it:
> SELECT * FROM (SELECT DISTINCT ON(refid_messages) refid_messages as msgid, *
> FROM messagehistorywithcontent WHERE
> (lower(ARRAY_TO_STRING(ARRAY[login,firstname,lastname,content,msgtitle], '
> ')) LIKE '%gg%') ORDER BY refid_messages DESC) as foo ORDER BY messagekind ASC
This is not really a solution, unless you don't care which of the rows
with a particular refid_messages value comes out. Usually, use of
"DISTINCT ON (x)" should be accompanied by "ORDER BY x, y", where y is
what you want to determine which row of a given x value comes out.
If you write it like this, you get the row with smallest y for each
x; or you could write "ORDER BY x, y DESC" to get the row with largest
y. See the DISTINCT ON example in the SELECT reference page.
regards, tom lane
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