On Wed, May 30, 2012 at 11:21 AM, Pavel Stehule <pavel.steh...@gmail.com>wrote:
> Hello
>
> create or replace function call_foo()
> returns void as $$
> declare r record;
> begin
> r := foo('Hello');
> raise notice ''% %', r.somerow, r.otherinfo;
> end;
> $$ language plpgsql;
>
It turns out i also need to define a type for the result record of `foo`,
because record can't reveal the structure of the result (it complains:
record "r" has no field "somerow").
I have to created this type:
create type foo_result as (somerow SomeTable, otherinfo varchar);
then change `r record;` to `r foo_result;` , no need change `foo` itself,
and it works now.
I don't know is this the best way to do this though.
>
> regards
>
> Pavel
>
> 2012/5/30 yi huang <yi.codepla...@gmail.com>:
> > I'm porting a oracle function to postgresql, which has signature like
> this:
> >
> > FUNCTION foo
> > ( seq IN varchar
> > , somerow OUT SomeTable
> > , otherinfo OUT varchar
> > )
> >
> > It's easy to port this function itself to postgresql, but i have problem
> to
> > execute this function and assign the results into variables:
> >
> > SELECT (foo(seq)).* INTO (v_somerow, v_otherinfo);
> >
> > It complains v_somerow can not be row type.
> >
> > How to handle the result of function foo?
> >
> > Best regards.
> > YiHuang.
>
--
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