Kyle Lanclos <lanc...@ucolick.org> writes:
> I spent some time last week staring at the code for the PostgreSQL
> B+-tree implementation. What I hoped to find, and was not immediately
> able to determine, was the Knuth order for the PostgreSQL B+-tree
> implementation. It is entirely possible that I simply got lost in the
> wrong C file.
> My goal is to make an informed assertion about the performance of
> a PostgreSQL B+-tree index as the quantity of records in our database
> grows more or less unbounded.
> To use a common reference, wikipedia states the following:
> Bayer & McCreight (1972), Comer (1979), and
> others define the order of B-tree as the
> minimum number of keys in a non-root node.
> Folk & Zoellick (1992) points out that terminology
> is ambiguous because the maximum number of keys
> is not clear. An order 3 B-tree might hold a
> maximum of 6 keys or a maximum of 7 keys.
> (Knuth 1998, p. 483) avoids the problem by defining
> the order to be maximum number of children (which
> is one more than the maximum number of keys).
Well, that would depend on the data type being indexed, which you did
not specify; and if it's a variable-length type then it's really hard to
give a concrete answer. For integer or int8 keys the answer is
typically about 400, though, depending on whether you're talking about
a 32- or 64-bit platform. Basically it's 4 bytes for line pointer,
plus 8 bytes for index tuple header, plus maxalign'ed size of the index
key, divided into page size (less a couple dozen bytes for page header).
You could increase the result by building with a page size of more than
the default 8K, though I've seen no recent experiments suggesting that
doing so is likely to be a win.
regards, tom lane
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