Instead of the joins you can use a subquery to get the first address. Or you can do the joins without the group by and use row_number() over(partition by companies.id) on the select list to label each company address with a number starting at 1. You can just keep rows that have row_number = 1. See http://www.postgresql.org/docs/current/static/tutorial-window.html to get the feeling how window functions work.
Kiriakos On Mar 12, 2012, at 3:35 PM, Alexander Reichstadt wrote: > Hi, > > the following statement worked on mysql but gives me an error on postgres: > > column "addresses.address1" must appear in the GROUP BY clause or be used in > an aggregate function > > I guess I am doing something wrong. I read the web answers, but none of them > seem to meet my needs: > > SELECT > companies.id,companies.name,companies.organizationkind,addresses.address1,addresses.address2,addresses.city,addresses.zip > FROM companies JOIN addresses_reference ON > companies.id=addresses_reference.refid_companies LEFT JOIN addresses ON > addresses_reference.refid_addresses=addresses.id GROUP BY companies.id; > > > What I did now was create a view based on above statement but without > grouping. This returns a list with non-distinct values for all companies that > have more than one address, which is correct. But in some cases I only need > one address and the problem is that I cannot use distinct. > > I wanted to have some way to display a companies list that only gives me the > first stored addresses related, and disregard any further addresses. > > Is there any way to do this? > > Thanks > Alex
