Hi,

On 30 January 2012 09:19, Adam Rich <ada...@sbcglobal.net> wrote:
> desired time, I want to show them the 5 times from the table that are
> closest to their
>
> input.  I expected to do this using abs() like such:
>
> select mytime from mytable order by abs(usertime-mytime) asc limit 5;
>
> However, the difference between times is an interval, and there appears to
> be no
>
> absolute value operator for those.  My next thought was to convert the
> interval

try this:
select mytime from mytable order by abs(extract(epoch from
(usertime-mytime))) asc limit 5;

-- 
Ondrej Ivanic
(ondrej.iva...@gmail.com)

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