The whole point of "with" is to factor out redundancy, and yet here you are
going and repeating the 2 "with" declarations; also the declarations have the
same names, which would be a problem, besides being redundant.
Try it like this instead:
with ...
(select ...)
union all
(select ...)
order by node
But moreover, I think you can avoid the union and doubled main selects, by
saying this instead:
with a as
(
select channel,node,accesses from storage where monthly = '11-06'
),
b as
(
select channel,node,accesses from storage where monthly = '11-07'
)
select
b.node
from a right join b on a.node=b.node
where a.accesses is null and b.channel in ('611 IVR', 'olam')
order by node
-- Darren Duncan
Joy Smith wrote:
with a as
(
select channel,node,accesses from storage where monthly = '11-06'
),
b as
(
select channel,node,accesses from storage where monthly = '11-07'
)
select
b.node
from a right join b on a.node=b.node
where a.accesses is null and b.channel = ('611 IVR')
order by node
UNION ALL
with a as
(
select channel,node,accesses from storage where monthly = '11-06'
),
b as
(
select channel,node,accesses from storage where monthly = '11-07'
)
select
b.node
from a right join b on a.node=b.node
where a.accesses is null and b.channel = 'olam'
order by node
--
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